Investigating the Resistance of Wires :: Papers

canvass the Resistance of Wires Aim To investigate how the diameter of a constantan equip allow for affect its resistance and hence the current menstruuming by dint of it. Prediction I predict that the thicker the diameter the less resistance thither will be. Reason In a metal, some of the electrons are fall by the wayside to move between the ions, to form a sea of electrons around the positivistic metal ions. Metals that are good conductors have much free electrons and thus these electrons move easily around the positive metal ions. However in metals that have fewer free electrons, the ions act as obstacles to the flow of electrons and thusly the equip has resistance. The current becomes stronger with the more than electrons that flow through a wire in one second. As the diameter increases the electrons will have more available routes between the ions to pass through per second, making the electron flow greater hence the current becoming stronger. See figures 1 and 2 IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE In a larger diameter, in that location IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEFigure 1 are more routes for free IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE electrons to travel IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE through. IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE In a smaller diameter, IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEFigure 2 there are fewer routes IMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGEIMAGE for the free electrons IMAGE to travel through. Plan I will set up a circuit consisting of a cell, ammeter, voltmeter and 50cm of constantan wire. The diameters I will use are as follows. 0.56mm, 0.43mm, 0.38 mm, 0.32mm, 0.27mm and 0.20mm. I will tax these diameters with a micrometer. I will take three readings of the current and strength difference for each different diameter of the wire and take an reasonable for V (potential difference thrifty by a voltmeter) and I (current measured by an ammeter) in order to get the most accurate results possible. I will then plot these results in two graphs one plotting V against I and another plotting the average resistance (using ohms law R=V/I) against the diameter.